Prologue
An online CTF competition by ACSC, this competition is qualification for competing in ICC for ASIA category.
Transclude of dist-pwr-tr4ce-d496d6a0966048feffde774458651ced1a411f2e.tar.gz
Write Up
Initial Analysis
We were given two files
If we looking at the description, we can have a several information about this challenge.
- This two files is a
power traces
andtext inputs
with AES Encryption - The flag is the
Key
of encryption - The experiment setup is like this:
- scope = chipwhisperer lite
- target = stm32f3
- AES key length = 16 bytes
By using google-fu, I can find the similar challenge with SquareCTF 2018 - C4 Leaky Power. codeforgeweb.wordpress.com.
Exploitation
By changing the path of file and print-ing the key from the original write-up, we can get the flag.
import base64
import binascii
import json
import re
import sys
import numpy as np
from cryptography.hazmat.backends import default_backend
from cryptography.hazmat.primitives.ciphers import Cipher, algorithms, modes
HW = [bin(n).count("1") for n in range(0,256)]
sbox=(
0x63,0x7c,0x77,0x7b,0xf2,0x6b,0x6f,0xc5,0x30,0x01,0x67,0x2b,0xfe,0xd7,0xab,0x76,
0xca,0x82,0xc9,0x7d,0xfa,0x59,0x47,0xf0,0xad,0xd4,0xa2,0xaf,0x9c,0xa4,0x72,0xc0,
0xb7,0xfd,0x93,0x26,0x36,0x3f,0xf7,0xcc,0x34,0xa5,0xe5,0xf1,0x71,0xd8,0x31,0x15,
0x04,0xc7,0x23,0xc3,0x18,0x96,0x05,0x9a,0x07,0x12,0x80,0xe2,0xeb,0x27,0xb2,0x75,
0x09,0x83,0x2c,0x1a,0x1b,0x6e,0x5a,0xa0,0x52,0x3b,0xd6,0xb3,0x29,0xe3,0x2f,0x84,
0x53,0xd1,0x00,0xed,0x20,0xfc,0xb1,0x5b,0x6a,0xcb,0xbe,0x39,0x4a,0x4c,0x58,0xcf,
0xd0,0xef,0xaa,0xfb,0x43,0x4d,0x33,0x85,0x45,0xf9,0x02,0x7f,0x50,0x3c,0x9f,0xa8,
0x51,0xa3,0x40,0x8f,0x92,0x9d,0x38,0xf5,0xbc,0xb6,0xda,0x21,0x10,0xff,0xf3,0xd2,
0xcd,0x0c,0x13,0xec,0x5f,0x97,0x44,0x17,0xc4,0xa7,0x7e,0x3d,0x64,0x5d,0x19,0x73,
0x60,0x81,0x4f,0xdc,0x22,0x2a,0x90,0x88,0x46,0xee,0xb8,0x14,0xde,0x5e,0x0b,0xdb,
0xe0,0x32,0x3a,0x0a,0x49,0x06,0x24,0x5c,0xc2,0xd3,0xac,0x62,0x91,0x95,0xe4,0x79,
0xe7,0xc8,0x37,0x6d,0x8d,0xd5,0x4e,0xa9,0x6c,0x56,0xf4,0xea,0x65,0x7a,0xae,0x08,
0xba,0x78,0x25,0x2e,0x1c,0xa6,0xb4,0xc6,0xe8,0xdd,0x74,0x1f,0x4b,0xbd,0x8b,0x8a,
0x70,0x3e,0xb5,0x66,0x48,0x03,0xf6,0x0e,0x61,0x35,0x57,0xb9,0x86,0xc1,0x1d,0x9e,
0xe1,0xf8,0x98,0x11,0x69,0xd9,0x8e,0x94,0x9b,0x1e,0x87,0xe9,0xce,0x55,0x28,0xdf,
0x8c,0xa1,0x89,0x0d,0xbf,0xe6,0x42,0x68,0x41,0x99,0x2d,0x0f,0xb0,0x54,0xbb,0x16)
def intermediate(pt, keyguess):
return sbox[pt ^ keyguess]
def do_cpa(pt, traces):
numtraces = np.shape(traces)[0]-1
numpoint = np.shape(traces)[1]
#Use less than the maximum traces by setting numtraces to something
#numtraces = 10
#Set 16 to something lower (like 1) to only go through a single subkey
bestguess = [0]*16
pge = [256]*16
for bnum in range(0, 16):
cpaoutput = [0]*256
maxcpa = [0]*256
for kguess in range(0, 256):
#Initialize arrays & variables to zero
sumnum = np.zeros(numpoint)
sumden1 = np.zeros(numpoint)
sumden2 = np.zeros(numpoint)
hyp = np.zeros(numtraces)
for tnum in range(0, numtraces):
hyp[tnum] = HW[intermediate(pt[tnum][bnum], kguess)]
#Mean of hypothesis
meanh = np.mean(hyp, dtype=np.float64)
#Mean of all points in trace
meant = np.mean(traces, axis=0, dtype=np.float64)
#For each trace, do the following
for tnum in range(0, numtraces):
hdiff = (hyp[tnum] - meanh)
tdiff = traces[tnum,:] - meant
sumnum = sumnum + (hdiff*tdiff)
sumden1 = sumden1 + hdiff*hdiff
sumden2 = sumden2 + tdiff*tdiff
cpaoutput[kguess] = sumnum / np.sqrt( sumden1 * sumden2 )
maxcpa[kguess] = max(abs(cpaoutput[kguess]))
bestguess[bnum] = np.argmax(maxcpa)
return bestguess
def b64d(data):
return base64.urlsafe_b64decode(str(data) + '=' * ((4 - len(data) % 4) % 4))
def main():
pt = np.load('textins.npy')
traces = np.load('traces.npy')
key = ''.join(chr(c) for c in do_cpa(pt, traces))
print(key)
# with open('instructions_corrected.jwe', 'rb') as f:
# enc = json.load(f)
# ciphertext = b64d(enc['ciphertext'])
# iv = b64d(enc['iv'])
# tag = b64d(enc['tag'])
# Don't check the tag because why would we?
# decryptor = Cipher(algorithms.AES(key), modes.GCM(iv, tag),
# backend=default_backend()).decryptor()
# plaintext = decryptor.update(ciphertext).decode()
# print(re.search(r'flag-[0-9a-f]{8,32}', plaintext).group(0))
if __name__ == '__main__':
main()
FLAG: ACSC{Pwr!4n4lyz}